![]() ![]() I use your table structure for numbers CREATE TABLE numbers ( n INTEGER NOT NULL PRIMARY KEY ) ) ENGINE=InnoDB DEFAULT CHARSET=latin1 AUTO_INCREMENT=6 `id_liste_track` mediumint(8) unsigned NOT NULL, `id_track` mediumint(8) unsigned NOT NULL AUTO_INCREMENT, Unlike Google Standard SQL, legacy SQL uses the comma as a UNION ALL operator rather than a CROSS JOIN operator. This means a subquery can itself contain other subqueries, subqueries can perform joins and grouping aggregations, etc. My table with the datetime CREATE TABLE IF NOT EXISTS `tracking` ( The full range of SQL operators are available in the subquery. If you prefer i could post a new thread with the same question but with my content, i don’t mind. Return a group count for every x minutes (15 is ok, i think i could change the time for my needs), AND that the results show no holes if no records : having a 0 value for those. So, of course i don’t use these names, but i aim the same goal : Maybe i’m confused with the the two post giving the answer :ĬEILING(UNIX_TIMESTAMP( timestamp)/900) 900īecause, i didn’t want to mess with the original post and use my own data stucture… If you have any questions regarding this method, please dont hesitate to ask. Remaining Seconds (TotalSeconds 60) (The is the modulo operator in T-SQL, which returns the remainder when dividing two integers.) Thus, we can write our SQL like this to return 3 integer columns (Hours, Minutes, Seconds. I won’t get the proper results : i’ll have 1 line for all the Null results. Insert Into YourTableName ( TenantCode, Instance, SupplierId, TimeSlice) Select TenantCode, Instance, SupplierId, StartDate + Number From Master.sptValues Where Type P And Number < 1000 I suspect this will be many times faster than your looping code. If we have a TotalSeconds, we can get: Hours (TotalSeconds / 3600) Remaining Minutes (TotalSeconds 3600) / 60. ![]() I got an error : Unknown column 'L.`timeslice`' in 'on clause'īut if i change : ON sliced.timeslice = L.`timeslice` WHERE sliced.`timeslice` >= ''ĪND sliced.`timeslice` < '' In fact, even if i change to SELECT FROM_UNIXTIME(įLOOR(UNIX_TIMESTAMP(`timestamp`)/900)*900 Someone told me I need to use a modulus for every 15 minutes, but I have no idea how to put it together. WHERE Timestamp BETWEEN ' 00:00:00' AND ' 23:59:59'īut still groups the count, the resultset still is: I have tried the following as well: SELECTįROM_UNIXTIME(FLOOR(UNIX_TIMESTAMP(timestamp)/(15*60))*15*60) I setup the db so there is a record at each 15 minute interval from 01:00:00 to 05:00:00 (total of 20 records). GROUP BY DATE( timestamp ), hour( timestamp ) When navigating to the SQL Performance dashboard (for either a Oracle or MSSQL database instance) on a Federator server, the dashboard on 4315800, WORKAROUND/SOLUTION:Run the attached script(s) on the Federator Master FMS. SELECT date_format( timestamp, '%h:00 %p' ) AS HOUR, count( * ) AS mycount Hello all, I have a sql statement that returns a count for every hour on my db, how do I change this so it returns a count for every 15 minutes of the hour? time slice sets the number of milliseconds that the Adaptive Server scheduler allows a task to run.
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